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0=0.1x^2+2.48x+5
We move all terms to the left:
0-(0.1x^2+2.48x+5)=0
We add all the numbers together, and all the variables
-(0.1x^2+2.48x+5)=0
We get rid of parentheses
-0.1x^2-2.48x-5=0
a = -0.1; b = -2.48; c = -5;
Δ = b2-4ac
Δ = -2.482-4·(-0.1)·(-5)
Δ = 4.1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.48)-\sqrt{4.1504}}{2*-0.1}=\frac{2.48-\sqrt{4.1504}}{-0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.48)+\sqrt{4.1504}}{2*-0.1}=\frac{2.48+\sqrt{4.1504}}{-0.2} $
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